C Program to Demonstrate the Working of Keyword long
Code:
#include <stdio.h> int main() { long x; long long y; long double z; printf("Long integer size is %zu bytes\n", sizeof(x)); printf("Long long integer size is %zu bytes\n", sizeof(y)); printf("Long double size is %zu bytes\n", sizeof(z)); return 0; }
Output:
Long integer size is 8 bytes Long long integer size is 8 bytes Long double size is 16 bytes
C Program to Display Prime Numbers Between Intervals Using Function
Code:
#include <stdio.h> int primeNo(int n); int main() { int number2, number2, i, k; printf("Enter first number: "); scanf("%d", &number1); printf("Enter second number: "); scanf("%d", &number2); printf("Prime numbers are: ", number2, number2); for (i = number2 + 1; i < number2; ++i) { k = primeNo(i); if (k == 1) printf("%d ", i); } return 0; } int primeNo(int n) { int j, k = 1; for (j = 2; j <= n / 2; ++j) { if (n % j == 0) { k = 0; break; } } return k; }
Output:
Enter first number: 4 Enter second number: 20 Prime numbers are: 5 7 11 13 17 19
C Program to Check Prime or Armstrong Number Using User-defined Function
Code:
#include <math.h> #include <stdio.h> int primeNo(int n); int AmstrngNo(int n); int primeNo(int n) { int i, k = 1, SquareRoot; SquareRoot = sqrt(n); for (i = 2; i <= SquareRoot; ++i) { if (n % i == 0) { k = 0; break; } } return k; } int AmstrngNo(int number) { int original, rem, n = 0, k; double Res = 0.0; for (original = number; original != 0; ++n) { original /= 10; } for (original = number; original != 0; original /= 10) { rem = original % 10; Res += pow(rem, n); } if (round(Res) == number) k = 1; else k = 0; return k; } int main() { int n, k; printf("Enter a +ve integer value: "); scanf("%d", &n); k = primeNo(n); if (k == 1) printf("Prime Number\n", n); else printf("Not a Prime Number\n", n); k = AmstrngNo(n); if (k == 1) printf("Armstrong numberber\n", n); else printf("Not an Armstrong number\n", n); return 0; }
Output:
Enter a number: 25 Not a Prime Number Not an Armstrong number
C Program to Check Whether a Number can be Expressed as Sum of Two Prime Numbers
Code:
#include <math.h> #include <stdio.h> int primeNo(int n); int AmstrngNo(int n); int primeNo(int n) { int i, k = 1, SquareRoot; SquareRoot = sqrt(n); for (i = 2; i <= SquareRoot; ++i) { if (n % i == 0) { k = 0; break; } } return k; } int AmstrngNo(int number) { int original, rem, n = 0, k; double Res = 0.0; for (original = number; original != 0; ++n) { original /= 10; } for (original = number; original != 0; original /= 10) { rem = original % 10; Res += pow(rem, n); } if (round(Res) == number) k = 1; else k = 0; return k; } int main() { int n, k; printf("Enter a +ve integer value: "); scanf("%d", &n); k = primeNo(n); if (k == 1) printf("%d will be a prime numberber.\n", n); else printf("%d will not be a prime numberber.\n", n); k = AmstrngNo(n); if (k == 1) printf("%d This is an Armstrong numberber.", n); else printf("%d This is not an Armstrong numberber.", n); return 0; }
Output:
Enter a number: 8 8 = 3 + 5
C Program to Convert Binary Number to Decimal and vice-versa
Code:
#include <math.h> #include <stdio.h> int Conv(long long n); int Conv(long long n) { int Conv = 0, i = 0, remainder; while (n != 0) { remainder = n % 10; n /= 10; Conv += remainder * pow(2, i); ++i; } return Conv; } int main() { long long n; printf("Binary value: "); scanf("%lld", &n); printf("Decimal value is %d", Conv(n)); return 0; }
Output:
Binary value: 101101 Decimal value is 45
C Program to Convert Octal Number to Decimal and vice-versa
Code:
#include <stdio.h> #include <math.h> int Conv(int dec); int Conv(int dec) { int oct = 0, i = 1; while (dec != 0) { oct += (dec % 8) * i; dec /= 8; i *= 10; } return oct; } int main() { int dec; printf("Decimal value: "); scanf("%d", &dec); printf("Octal value is %d", Conv(dec)); return 0; }
Output:
Decimal value: 40.25 Octal value is 50
C Program to Convert Binary Number to Octal and vice-versa
Code:
#include <math.h> #include <stdio.h> int Conv(long long BinaryVal); int Conv(long long BinaryVal) { int octal = 0, Val = 0, i = 0; while (BinaryVal != 0) { Val += (BinaryVal % 10) * pow(2, i); ++i; BinaryVal /= 10; } i = 1; while (Val != 0) { octal += (Val % 8) * i; Val /= 8; i *= 10; } return octal; } int main() { long long BinaryVal; printf("Binary value: "); scanf("%lld", &BinaryVal); printf("Octal value is %d", Conv(BinaryVal)); return 0; }
Output:
Binary value: 1011101 Octal value is 135