In this blog, we will create a program to find the sum of even numbers from an array in the C++ programming language.

Algorithm to create the respective code

Here we can use a modular operator to find even numbers in an array

if n%2==0, n is an even number – if the number is even, the remainder is zero.

C++ program to find the sum of even numbers from an array

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int evenSum=0;
    int i,size;
    cout<<"Enter the size of the array: ";
    cin>>size;
    int arr[size];
    cout<<"Enter the Array elements: ";

    for(i=0; i<size; i++)
    {
            cin>>arr[i];
    }
    for(i=0; i<size; i++)
    {
        if(arr[i]%2==0)
        evenSum=evenSum+arr[i];
    }
   
    cout<<"\nThe sum of even numbers are:"<<evenSum;
    getch();
    return 0;
}

Output of the above code

Explanation of the above code

• To begin with, it declares and initializes two variables:  evenSum=0, and size.
• It also receives input from the user regarding the length of the array.
• It then defines an array without including elements.
• Then the elements for the array are received from the user.
• Then, a “for loop” is used to add the elements one by one to the array.
• Then, a second “for” loop is used to select elements one by one from the array to determine which numbers are even.
• Next, “if” statements are used to find the number, and if it is even, it is added to the even sum. If the number is not even, it is neglected.
• Finally, the sum of even numbers is displayed.